Hiya, I'm new here!
So I'm having some problem with these physics problems, I have a lot more, but I don't want to bother you guys with so many problems!! I'm new to physics and I just do not understand these problems. Any help on any problem is really appreciated! These are from my review sheet, I have a test on Tuesday and it's killing me not being able to figure out how to solve so many of the problems!
1.) A proton has mass 1.7x10^-27 kg. What is the magnitude of the impulse required in the direction of motion to increase its speed from 0.992c to 0.995c?
2.)
You were driving a car with velocity %26lt;20, 0, 13%26gt; m/s. You quickly turned and braked, and your velocity became %26lt;10, 0, 18%26gt; m/s. The mass of the car was 1100 kg. The maneuver took 5 seconds.
They want these as vectors:
(a) What was the change in the momentum?
(b) What was the impulse that acted on the car?
(c) What was the average net (vector) force acting on the car?
3.)
(a) A runner starts from rest and in 3 s reaches a speed of 10 m/s. If we assume that the speed changed at a constant rate (constant net force), what was the average speed during this 3 s interval?
(b) How far did the runner go in this 3 s interval?
(c) The driver of a car traveling at a speed of 17 m/s slams on the brakes and comes to a stop in 4 s. If we assume that the speed changed at a constant rate (constant net force), what was the average speed during this 4 s interval?
(d) How far did the car go in this 4 s interval?
-I hope I'll get some feedback! Thank you guys for your time!!Intro Physics Problems?1) the photon will always travel with the speed of light. But if you have a medium with refractive index n then the speed of light in this medium is c'=c/Sqrt[n]. Lets now consider that the photon is an ordinary mass, to increase the speed you need to increase his energy. Remember E=m c^2. You can calculate this way theenergy needed. Impuls remain the same p= m v. m is the dinamic mase. If 1.7x10^-27 is the rest mas m0 then m=m0/Sqrt[1-(v/c)^2] with this you can calculate the difrence in impuls which is p1-p2=m(v1)v1-m (v2)v2
2)a)Assuming the same as in 1) you can resolve this by replacing with vectors you get b) the diffrence in impuls an then multiply this vectorial to the distance from the coordinate system.
b) you get it first in a)
c)net vector was the aswere in b/ time
3)a) avrage speed is 10 ms /2
b) avrage speed times time=15 m
c)17/2=8.5m/s^2
d)34 m
